3m^2+9m=3030

Solution for 3m^2+9m=3030 equation:

3m^2+9m=3030

We move all terms to the left:

3m^2+9m-(3030)=0

a = 3; b = 9; c = -3030;
Δ = b2-4ac
Δ = 92-4·3·(-3030)
Δ = 36441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{36441}=\sqrt{9*4049}=\sqrt{9}*\sqrt{4049}=3\sqrt{4049}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{4049}}{2*3}=\frac{-9-3\sqrt{4049}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{4049}}{2*3}=\frac{-9+3\sqrt{4049}}{6}
$